@Feley That same logic could then be applied to:
99/100 + 99/100 = 198/100?
Which is clearly incorrect 
Because even though your chances are 99/100 both time, it doesn’t mean you are guaranteed to get it.
@Sniff is correct with the 2 attempts at 3% != 6%, because when you add two fractions, you add the denominators together, AND the numerators together, making it:
3/100 + 3/100 = 6/200.
And thus, rounding down gives us… 3/100.
Yay, maths <3
(or “math”, if you forget that the word is plural)
@Feley That same logic could then be applied to:
99/100 + 99/100 = 198/100?
Which is clearly incorrect Because even though your chances are 99/100 both time, it doesn’t mean you are guaranteed to get it.
@Sniff is correct with the 2 attempts at 3% != 6%, because when you add two fractions, you add the denominators together, AND the numerators together, making it:
3/100 + 3/100 = 6/200.
And thus, rounding down gives us… 3/100.
Yay, maths <3
(or “math”, if you forget that the word is plural)[/quote]
Nope, Brontesaur is correct with his last post I wasn just pointing that its impossible to get same percentage for two cases because if you buy 30 cases it sure is higher chance of getting cobalt than 3%
You don’t add denominators, otherwise when you add two fractions that are the same, the result would be the same. 1/2 + 1/2 is 1, not 2/4 (1/2). That’s extremely basic maths. :#
Bought me 5 expert cases earlier so I could trade up. Very cost-effective means of getting the bling I want. 
I really like that these have been implemented and I found the value good enough to spend my money on them.
@Feley That same logic could then be applied to:
99/100 + 99/100 = 198/100?
Which is clearly incorrect Because even though your chances are 99/100 both time, it doesn’t mean you are guaranteed to get it.
@Sniff is correct with the 2 attempts at 3% != 6%, because when you add two fractions, you add the denominators together, AND the numerators together, making it:
3/100 + 3/100 = 6/200.
And thus, rounding down gives us… 3/100.
Yay, maths <3
(or “math”, if you forget that the word is plural)[/quote]
It’s not 6%, and it’s not 3/100, because probability doesn’t work by adding the 2 together in those ways. Rather it’s around 5.9% as I worked out above.
@Feley That same logic could then be applied to:
99/100 + 99/100 = 198/100?
Which is clearly incorrect Because even though your chances are 99/100 both time, it doesn’t mean you are guaranteed to get it.
@Sniff is correct with the 2 attempts at 3% != 6%, because when you add two fractions, you add the denominators together, AND the numerators together, making it:
3/100 + 3/100 = 6/200.
And thus, rounding down gives us… 3/100.
Yay, maths <3
(or “math”, if you forget that the word is plural)[/quote]
It’s not 6%, and it’s not 3/100, because probability doesn’t work by adding the 2 together in those ways. Rather it’s around 5.9% as I worked out above.
[/quote]
Which may as well be round up to 6% because .1% is negligible.
@Feley That same logic could then be applied to:
99/100 + 99/100 = 198/100?
Which is clearly incorrect Because even though your chances are 99/100 both time, it doesn’t mean you are guaranteed to get it.
@Sniff is correct with the 2 attempts at 3% != 6%, because when you add two fractions, you add the denominators together, AND the numerators together, making it:
3/100 + 3/100 = 6/200.
And thus, rounding down gives us… 3/100.
Yay, maths <3
(or “math”, if you forget that the word is plural)[/quote]
It’s not 6%, and it’s not 3/100, because probability doesn’t work by adding the 2 together in those ways. Rather it’s around 5.9% as I worked out above.
[/quote]
Which may as well be round up to 6% because .1% is negligible.[/quote]
And that .1% is probably the percentage to get both cobalts… so it makes up for that…
[quote=“Clown;81809”]
Which may as well be round up to 6% because .1% is negligible.[/quote]
No, I wouldn’t round up because it shouldn’t be confused as 3% + 3% = 6%.
[quote=“Feley;81811”]
And that .1% is probably the percentage to get both cobalts… so it makes up for that…[/quote]
That 5.9% figure already includes the chance to get both as cobalts. It’s .03 * .03 = 0.09% chance to get both as cobalts, and 5.82% to get 1 cobalt only. It’s not 5.9% to get 1 cobalt + 0.1% to get 2 cobalts = 6%.
[quote=“brontesaur;81816”]
[quote=“Feley;81811”]
And that .1% is probably the percentage to get both cobalts… so it makes up for that…[/quote]
That 5.9% figure already includes the chance to get both as cobalts. It’s .03 * .03 = 0.09% chance to get both as cobalts, and 5.82% to get 1 cobalt only. It’s not 5.9% to get 1 cobalt + 0.1% to get 2 cobalts = 6%.[/quote]
Yup that is what I am saying lol… If you have 5.82% to get 1 cobalt and 0.09% to get two cobalts… that makes for that 0.09% missing… If you didn’t understand (because I don’t know to explain things very well :P) = 5.82% * 1 cobalt = 5.82 p + 0.09% * 2 cobalts = 0.18 p
lets say p stands for points, because those sure aren’t percentages… 5.82 + 0.18 = 6
We’re not adding fractions though, we’re working out a %. And you can’t add up to over 100% when doing probability. So the fractions you have from the percentage values, you add the two values together like I said to get the overall percentage chance. :s
We’re not adding fractions though, we’re working out a %. And you can’t add up to over 100% when doing probability. So the fractions you have from the percentage values, you add the two values together like I said to get the overall percentage chance. :s [/quote]
You said “when you add fractions” and besides, that’s still wrong. You basically said you have an equal chance of getting a cobalt from 100 cases as you do from 200.
We’re not adding fractions though, we’re working out a %. And you can’t add up to over 100% when doing probability. So the fractions you have from the percentage values, you add the two values together like I said to get the overall percentage chance. :s [/quote]
You said “when you add fractions” and besides, that’s still wrong. You basically said you have an equal chance of getting a cobalt from 100 cases as you do from 200.[/quote]
You pretty much do. 3/100. You just do it 200 times. https://en.wikipedia.org/wiki/Gambler's_fallacy
We’re not adding fractions though, we’re working out a %. And you can’t add up to over 100% when doing probability. So the fractions you have from the percentage values, you add the two values together like I said to get the overall percentage chance. :s [/quote]
You said “when you add fractions” and besides, that’s still wrong. You basically said you have an equal chance of getting a cobalt from 100 cases as you do from 200.[/quote]
You pretty much do. 3/100. You just do it 200 times. https://en.wikipedia.org/wiki/Gambler's_fallacy[/quote]
Sorry, let me rephrase. What Faraleth said was just each individual case has a 3% chance of getting a cobalt, we already knew that. Statistically, you’d get 5-6 though.
PS. I don’t get what gambler’s fallacy had to do with what I said.
[quote=“Feley;81837”]Yup that is what I am saying lol… If you have 5.82% to get 1 cobalt and 0.09% to get two cobalts… that makes for that 0.09% missing… If you didn’t understand (because I don’t know to explain things very well :P) = 5.82% * 1 cobalt = 5.82 p + 0.09% * 2 cobalts = 0.18 p
lets say p stands for points, because those sure aren’t percentages… 5.82 + 0.18 = 6[/quote]
It’s not 0.09% * 2, because you can only get 2 cobalts in one situation whereas you can get 1 cobalt in 2 situations: either first case has once and second doesn’t, or the second has it and first doesn’t. So you only multiply the 1 cobalt case by 2, not the 2 cobalt case. So the 5.91% stands.
Like I said, you don’t add in this case. The formula is different.
It’s not 100 + 100 = 200 times, because these 2 rolls are discrete events that don’t affect each other.
Also it’s not the gambler’s fallacy. Gambler’s fallacy is saying that individual events remain the same percentage chance regardless of previous outcomes. What we’re talking about here is not an individual event, it’s 2 cases rolled at the same time.
Methinks a lot of people here need to brush up on their middle school maths 
I never pay money for free games, so i like the free cases that are dropped.
I like how this thread turned into people getting egos about nitpicky math that is abstract enough to be nearly irrelevant. The point is you have a slim ass chance of ever getting a cobalt out of a free case. Hell with your math.
[quote=“brontesaur;82291”][quote=“Feley;81837”]Yup that is what I am saying lol… If you have 5.82% to get 1 cobalt and 0.09% to get two cobalts… that makes for that 0.09% missing… If you didn’t understand (because I don’t know to explain things very well :P) = 5.82% * 1 cobalt = 5.82 p + 0.09% * 2 cobalts = 0.18 p
lets say p stands for points, because those sure aren’t percentages… 5.82 + 0.18 = 6[/quote]
It’s not 0.09% * 2, because you can only get 2 cobalts in one situation whereas you can get 1 cobalt in 2 situations: either first case has once and second doesn’t, or the second has it and first doesn’t. So you only multiply the 1 cobalt case by 2, not the 2 cobalt case. So the 5.91% stands.
[/quote]
I know that… That is why I said those aren’t percentages, but rather points because I would be as much happy to have a chance of getting 5 cobalts for 1% as to have a chance of getting 1 cobalt for 5%… That is why I say chance of getting 2 cobalts I count as double Points …
When people have spent $2000 of real money on cases, I think you’ll find 1% is very relevant.
You lost me at this points thing. Never mind then. B)
“When people have spent $2000 of real money on cases, I think you’ll find 1% is very relevant.”
That’s a poor excuse for being rude and telling people they should re-learn middle school math.
