So I made this disscussion on how I had the repeat cobalt BL32 fletcher, same camo and all. so I traded in one of them and a ok cobalt sawbonez as I don’t play him much, i got the same card, however this time I got it in the opposite camo so although I was pissed, it wasn’t as bad as it could be. Now however, i decided since I wasn’t using the cards much, I traded both in and hoped and prayed for the A31 Shard, I was rewarded WITH THE BL32 SHARD, to put that in prospective, I, in total got 4 cobalts, 2 BL32 Fragments, 2 BL32 Shards, there are 9 total loadout cards times 2 for camos, you have a 1 in 18 chance to get any specific card, and to get 2 of the same card in the same camo, you have a 1 in 324 chance. to get 4 of the same card DISREGARDING camo is 1/6561… for 2 different repeat cobalts, 1/104976.
I DEMAND A REFUND
(MATH, if you like)
for 1 fragment Bl32
1/18 chance
for 2 fragment BL32s
1/18 * 1/18 = 1/324
for I Shard BL32
1/18
for 2 shard BL32s
1/18 * 1/18 = 1/324
for 2 of each (Shard and Fragment BL32s)
1/324 *1/324 = 1/104976
for 4 of the same card
1/9^4 = 1/6561
PS: Please speak up if you see an error in my math, or type up I guess.
PSS: Because of how rng works on computers, technically, this math is wrong, if you use a random number generator on your calculator, it won’t roll dice every time, it will have something like a spinner that goes around the numbers at the same speed, if your got, say 30 people to use a calculators random nubers genorator, say 30 times from numbers 1-10 you have a brilliant chance to get 2 or more people to have the same exact 30 numbers.